C++ 用函数 迭代法 求x=均示困方婷效应宽余根号a

问题补充说明：#include #include double diedai(double m,double a); static double n; void main() { double a; cin>>a; cout<1e-7) di... #include#includedouble diedai(double m,double a);static double n;void main(){ double a; cin>>a; cout<1e-7) diedai(n,a); return n;}哪儿错了 展开

1234567891011121314151617#include<io360问答stream.h>#include<math.h>dou知士雨故机村重温钟理ble diedai(double m,double a);static d怕考多州手掉境批委ouble n;void main(){    double a;    cin>>a;    cout<<diedai(a,a)<<endl;}double diedai(double m,double a){    n=1.0/2者只失次械照须亮刑频*(m+a/m); //1/2=0          1.0/2=0.5    if(fabs(m-n)>1e-7)        diedai(n,a);    return n;}

标签：根号,迭代法,C++